如何分解一个元组以便它可以作为参数列表传递?
问题描述
假设我有一个这样的方法定义:
Let's say I have a method definition like this:
def myMethod(a, b, c, d, e)
然后,我有一个变量和一个像这样的元组:
Then, I have a variable and a tuple like this:
myVariable = 1
myTuple = (2, 3, 4, 5)
有没有一种方法可以传递爆炸元组,以便我可以将其成员作为参数传递?像这样的东西(虽然我知道这不起作用,因为整个元组被认为是第二个参数):
Is there a way I can pass explode the tuple so that I can pass its members as parameters? Something like this (although I know this won't work as the entire tuple is considered the second parameter):
myMethod(myVariable, myTuple)
如果可能,我想避免单独引用每个元组成员...
I'd like to avoid referencing each tuple member individually if possible...
解决方案
您正在寻找 参数解包操作符*
:
myMethod(myVariable, *myTuple)
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