在 PL/SQL 中将逗号分隔的字符串转换为数组
如何将逗号分隔的字符串转换为数组?
How do I convert a comma separated string to a array?
我有输入 '1,2,3'
,我需要把它转换成一个数组.
I have the input '1,2,3'
, and I need to convert it into an array.
推荐答案
Oracle 提供了内置函数 DBMS_UTILITY.COMMA_TO_TABLE.
Oracle provides the builtin function DBMS_UTILITY.COMMA_TO_TABLE.
不幸的是,这个不适用于数字:
Unfortunately, this one doesn't work with numbers:
SQL> declare
2 l_input varchar2(4000) := '1,2,3';
3 l_count binary_integer;
4 l_array dbms_utility.lname_array;
5 begin
6 dbms_utility.comma_to_table
7 ( list => l_input
8 , tablen => l_count
9 , tab => l_array
10 );
11 dbms_output.put_line(l_count);
12 for i in 1 .. l_count
13 loop
14 dbms_output.put_line
15 ( 'Element ' || to_char(i) ||
16 ' of array contains: ' ||
17 l_array(i)
18 );
19 end loop;
20 end;
21 /
declare
*
ERROR at line 1:
ORA-00931: missing identifier
ORA-06512: at "SYS.DBMS_UTILITY", line 132
ORA-06512: at "SYS.DBMS_UTILITY", line 164
ORA-06512: at "SYS.DBMS_UTILITY", line 218
ORA-06512: at line 6
但是有一个小技巧,用'x'前缀元素,它的工作原理:
But with a little trick to prefix the elements with an 'x', it works:
SQL> declare
2 l_input varchar2(4000) := '1,2,3';
3 l_count binary_integer;
4 l_array dbms_utility.lname_array;
5 begin
6 dbms_utility.comma_to_table
7 ( list => regexp_replace(l_input,'(^|,)','1x')
8 , tablen => l_count
9 , tab => l_array
10 );
11 dbms_output.put_line(l_count);
12 for i in 1 .. l_count
13 loop
14 dbms_output.put_line
15 ( 'Element ' || to_char(i) ||
16 ' of array contains: ' ||
17 substr(l_array(i),2)
18 );
19 end loop;
20 end;
21 /
3
Element 1 of array contains: 1
Element 2 of array contains: 2
Element 3 of array contains: 3
PL/SQL procedure successfully completed.
问候,罗布.
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