从 Python 中的元组列表中迭代查找/替换

2022-01-20 00:00:00 python django list iteration tuples

问题描述

我有一个元组列表，每个元组都包含我想应用于字符串的查找/替换值.这样做最有效的方法是什么?我将反复应用它，所以性能是我最关心的问题.

I have a list of tuples, each containing a find/replace value that I would like to apply to a string. What would be the most efficient way to do so? I will be applying this iteratively, so performance is my biggest concern.

更具体地说，processThis() 的内部结构是什么样的?

More concretely, what would the innards of processThis() look like?

x = 'find1, find2, find3'
y = [('find1', 'replace1'), ('find2', 'replace2'), ('find3', 'replace3')]

def processThis(str,lst):
     # Do something here
     return something

>>> processThis(x,y)
'replace1, replace2, replace3'

谢谢大家！

解决方案

可以考虑使用re.sub:

import re
REPLACEMENTS = dict([('find1', 'replace1'),
                     ('find2', 'replace2'),
                     ('find3', 'replace3')])

def replacer(m):
    return REPLACEMENTS[m.group(0)]

x = 'find1, find2, find3'
r = re.compile('|'.join(REPLACEMENTS.keys()))
print r.sub(replacer, x)

相关文章