我如何使用“日期"sql server 中的数据类型?
你好朋友，我需要你的帮助，当我尝试在表中创建数据类型为Date"的列时，它给了我错误，我无法在此处添加它，这是我的代码
Hello Friends I need your help please when I'm trying to create column in table with data type "Date" it gives me error and I can't add it here is my code
Create table Orders (
Order_ID INT Primary Key,
Book_name varchar(100) ,
isbn varchar(100) ,
Customer_ID INT Foreign key references Customer,
Order_date date,
);
另一件事它需要我来获取创建之前的东西的日期
another thing it requires from me to get date of something which is before created one
更清楚:询问的查询表明要在 8 月 2 日之前找到日期我该怎么做
to be more clear: the query asked indicates to find date before 2 of August How can I do that
我尝试输入这样的数据
Insert Into Orders(Order_ID, Book_name, isbn, Customer_ID, Order_date) values (1, 'Design User Interface',9345678210123, 1, '02-08-2015');
Insert Into Orders(Order_ID, Book_name, isbn, Customer_ID, Order_date) values (2, 'Fire',9654693261489, 1, '05-08-2015');
Insert Into Orders(Order_ID, Book_name, isbn, Customer_ID, Order_date) values (3, 'The Odyssey',9654864332511, 2, '01-08-2015');
Insert Into Orders(Order_ID, Book_name, isbn, Customer_ID, Order_date) values (4, 'Anatomy',9654877777755, 2, '30-07-2015');
Insert Into Orders(Order_ID, Book_name, isbn, Customer_ID, Order_date) values (5, 'Surgery',9654864951753, 2, '01-07-2015');
但是，它只接受前 3 个插入和后两个它给我错误:/
but, it accept only first 3 insertion and last two it gives me error :/
推荐答案
最后两个"你没有问题.
You do not have a problem with the "last two".
但是，您确实对所有这些都存在问题，但是一点一点.
However, you do have a problem with all of them, but one point after the other.
您的日期被解释为 MM-DD-YYYY.这种解释取决于您系统的文化.前三个正在变成错误的日期，但有效.第 4 次中断，第 5 次从未执行(由于之前的错误).
Your dates are interpreted as MM-DD-YYYY. This intrepretation is depenent on your system's culture. The first three are turning into wrong dates but work. The 4th breaks and the fifth is never executed (due to the error before).
所以实际的错误在于第 4 行.
So the actual error lies on line 4.
无论何时处理日期，都应使用独立于文化的格式.最好使用以下任一方式-
Whenever you deal with dates, use culture independent formats. It is better to use either of the following-
20150730 (=> the 30th of July in 2015)
ODBC 格式
{d'2015-07-30'} or {t'23:30:59'} or {ts'2015-07-30 23:30:59'}
ISO 8601
'2015-07-30T00:00:00'
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