从另一个具有相同用户名的表中更新表值
我有两个表,有一个名为 user_name
的列,分别是 table_a
、table_b
.
I have two tables, with a same column named user_name
, saying table_a
, table_b
.
我想,从table_b
、column_b_1
、column_b2
复制到table_b1
、column_a_1
、column_a_2
,分别是user_name
相同的地方,在SQL语句中怎么做?
I want to, copy from table_b
, column_b_1
, column_b2
, to table_b1
, column_a_1
, column_a_2
, respectively, where the user_name
is the same, how to do it in SQL statement?
推荐答案
只要你有合适的索引,这应该没问题:
As long as you have suitable indexes in place this should work alright:
UPDATE table_a
SET
column_a_1 = (SELECT table_b.column_b_1
FROM table_b
WHERE table_b.user_name = table_a.user_name )
, column_a_2 = (SELECT table_b.column_b_2
FROM table_b
WHERE table_b.user_name = table_a.user_name )
WHERE
EXISTS (
SELECT *
FROM table_b
WHERE table_b.user_name = table_a.user_name
)
sqlite3 中的 UPDATE 不支持 FROM 子句,这使得它比在其他 RDBMS 中.
UPDATE in sqlite3 does not support a FROM clause, which makes this a little more work than in other RDBMS.
如果性能不令人满意,另一种选择可能是使用 select 为 table_a 构建新行并与 table_a 连接到临时表中.然后从table_a中删除数据并从临时数据中重新填充.
If performance is not satisfactory, another option might be to build up new rows for table_a using a select and join with table_a into a temporary table. Then delete the data from table_a and repopulate from the temporary.
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