解压元组的pythonic方法是什么?
问题描述
这很难看.有什么更 Pythonic 的方式来做到这一点?
This is ugly. What's a more Pythonic way to do it?
import datetime
t= (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6])
解决方案
一般可以使用func(*tuple)语法.您甚至可以传递元组的一部分，这看起来就像您在这里尝试做的那样:
Generally, you can use the func(*tuple) syntax. You can even pass a part of the tuple, which seems like what you're trying to do here:
t = (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(*t[0:7])
这被称为 unpacking 元组，也可以用于其他可迭代对象(例如列表).这是另一个示例(来自 Python 教程):
This is called unpacking a tuple, and can be used for other iterables (such as lists) too. Here's another example (from the Python tutorial):
>>> range(3, 6) # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args) # call with arguments unpacked from a list
[3, 4, 5]
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