mySQL 查询键值对
我正在对 wordpress 表 (postmeta) 进行查询.该表有键和值,我需要一个查询来获取所有匹配key1"等于value1"和key2"等于value2"的行,按value2排序
I am doing a query on a wordpress table (postmeta). The table has keys and values and I need a query that will get all rows that match "key1" equal to "value1" and "key2" equal to "value2" ordered by value2
该表基本上有 id、postid、key 和 value 列.
The table basically has an id, postid, key and value columns.
我什至不知道从哪里开始.我可以找到一个很好的值,即 ... where key='featured' &值=真.但我需要按行的值排序的前 25 个,其中 key='hits' 意味着我需要这些特色行的相应命中键的值
I am not sure even where to start. I can find one value fine ie ... where key='featured' & value=true. But I need the top 25 ordered by the value of the rows where key='hits' meaning I need the value of the corresponding hits key for those featured rows
我不知道该怎么做.
TIA
推荐答案
根据您提供的有限详细信息,很难确切说明如何执行此操作.但是当您想返回键/值对时,您可以使用以下方法.
It is difficult to say exactly how to do this with the limited details that you provided. But when you want to return key/value pairs you can use the following.
您可以多次加入您的桌子:
You can join on your table multiple times:
select p1.postid,
p1.value Featured,
p2.value Hits
from postmeta p1
left join postmeta p2
on p1.postid = p2.postid
and p2.key = 'hits'
where p1.key ='featured';
参见SQL Fiddle with Demo
或者你可以使用带有 CASE
表达式的聚合函数(使用 sum()
假设一个数值,你可以使用 max()
/min()
用于字符串值:
Or you can use an aggregate function with a CASE
expression (using sum()
assumes a numeric value, you can use max()
/min()
for string values:
select postid,
sum(case when `key` = 'featured' then value end) Featured,
sum(case when `key` = 'hits' then value end) Hits
from postmeta
group by postid
参见SQL Fiddle with Demo
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