获取设定年份的第一天
declare @coyear varchar (max)
set @coyear = '2018'
SELECT (YEAR(DATEADD(year,0,@coyear)))
我已将 @coyear
设置为 2018 年,结果为 2018 年.我想要我为一年设置的一年中的第一天.例如,当我在 @coyear
中通过 2018 时,我希望结果为 2018-01-01.
I have set @coyear
as 2018 and I am getting 2018 in result.
I want first day of the year which I have set for year.
For example when I pass 2018 in @coyear
I want 2018-01-01 in result.
推荐答案
DATEFROMPARTS
似乎是更好的解决方案:
DATEFROMPARTS
would seem a better solution:
DECLARE @CoYear int; --Why would you need 2GB/2 Billion characters for a year?
SET @CoYear = 2018;
SELECT DATEFROMPARTS(@CoYear, 1, 1);
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