Pyqt如何获取小部件的尺寸
问题描述
我目前正在开发一个无法使用模式窗口的应用程序(由于某些应用程序限制).但是，在某些情况下，我想模拟一个弹出窗口.为此，我动态创建了一个以 centralwidget 作为父级的小部件，并使用 move() 方法将其放置在我想要的位置.我想知道是否有办法在给定时间获取小部件的尺寸(考虑到 mainWindow 可以随时调整大小)，以便我能够将占位符弹出窗口(一个简单的小部件)居中中央小部件.
I am currently developing an application in which i cannot use modal windows (due to some application constraints). However, in some cases i would like to simulate a popup window. To do so i dynamically create a widget that has the centralwidget as parent and i use the move() method to place it where i want. I would like to know if there is a way to get a widget's dimensions at a given time (considering the mainWindow can be resized at any time) so that i will be able to center the placeholder popup (a simple widget) at the middle of the centralwidget.
谢谢
解决方案
你可以使用frameGeometry 或 geometry 取决于 您的需求.
相关文章