XML to SQL 问题 - 如何获取元素的位置
我试图在 sql 中获取 XML 节点元素的位置,但它没有给我正确的结果,@Shungo 建议使用该方法
I am trying to get the position of an element of an XML node in sql , and it is not giving me correct results , the approach was suggested by @Shungo
这是代码:
declare @xmlVar xml ='
<A specVersion="2.09">
<B id="1" type="Regular">
<C>
<D>
<E actioncode="A" date="06/13/2018 09:20" />
<E actioncode="B" date="06/13/2018 09:20" />
</D>
<D>
<E actioncode="C" date="06/13/2018 09:20" />
</D>
</C>
</B>
<B id="2" type="Regular">
<C>
<D>
<E actioncode="D" date="06/13/2018 09:20" />
</D>
</C>
</B>
</A>' ;
WITH Tally(Nmbr) AS
(
SELECT TOP (SELECT @xmlVar.value(N'count(/A/B/C/D)','int'))
ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM master..spt_values --just a pre-filled table with many rows
)
SELECT Nmbr
,e.value(N'@actioncode[1]','nvarchar(max)') AS Employee
FROM Tally
OUTER APPLY(SELECT @xmlVar.query(N'/A/B/C/D[sql:column("Nmbr")]')) AS A(ds)
OUTER APPLY ds.nodes(N'D/E') AS B(e);
上面的查询给出了错误的结果:
The above query is giving wrong results :
1 A
1 B
1 D
2 C
3 NULL
预期输出:
1 A
1 B
2 C
3 D
任何帮助将不胜感激.谢谢.
Any help would be appreciated . Thanks.
推荐答案
嗯,这和之前的完全不一样了...
Well, this is quite different to the one before...
看起来,您希望将 <D>
节点放在任何位置.这有帮助吗?
As it looks, you want to take <D>
nodes whereever they are placed. Does this help?
WITH Tally(Nmbr) AS
(
SELECT TOP (SELECT @xmlVar.value(N'count(//D)','int'))
ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM master..spt_values --just a pre-filled table with many rows
)
SELECT Nmbr
,e.value(N'@actioncode[1]','nvarchar(max)') AS Employee
FROM Tally
OUTER APPLY(SELECT @xmlVar.query(N'//D').query(N'/D[sql:column("Nmbr")]')) AS B(ds)
OUTER APPLY ds.nodes(N'D/E') AS C(e);
第一个应用程序将使用深度搜索(使用//D
)来获取仅包含这些节点的派生 XML.其余的和以前一样.
The first apply will use the deep search (with //D
) to get a derived XML including these nodes only. The rest is rather the same as before.
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