tsql 函数拆分字符串
我想知道是否有人可以帮助我.
I wonder if anyone can help me.
我需要一个 tsql 函数来分割给定的值,例如:
I need a tsql function to split a given value such as:
1) 00 Not specified
3) 01-05 Global WM&BB | Operations
2) 02-05-01 Global WM&BB | Operations | Operations n/a
我需要得到这样的结果:
I need to get a result like this:
cat1 cat1descr cat2 cat2descr cat3 cat3descr
----------------------------------------------------------------
00 Not especified null null null null
01 Global WM&BB 05 Operations null null
01 Global WM&BB 05 Operations 01 Operations n/a
结果将始终有 6 列
select funcX('00 未指定');
select funcX('00 Not specified');
cat1 cat1descr cat2 cat2descr cat3 cat3descr
----------------------------------------------------------------
00 Not especified null null null null
推荐答案
这将适用于 SQL Server 2005 和 SQL Server 2008.我假设您的第一个数字序列固定为 1、2、或 3. 您可以使用较少的级联 CTE 来完成此操作,但我发现 SUBSTRING/CHARINDEX/LEN 语法很快就会变得非常难以阅读和调试.
This will work on SQL Server 2005 and SQL Server 2008. I have assumed that your first sequence of digits is fixed to 2-digit groups of 1, 2, or 3. You can do this with fewer cascading CTEs but I find the SUBSTRING/CHARINDEX/LEN syntax can quickly become very difficult to read and debug.
DECLARE @foo TABLE
(
bar VARCHAR(4000)
);
INSERT @foo(bar) SELECT '00 Not specified'
UNION ALL SELECT '01-05 Global WM&BB | Operations'
UNION ALL SELECT '02-05-01 Global WM&BB | Operations | Operations n/a';
WITH split1 AS
(
SELECT
n = SUBSTRING(bar, 1, CHARINDEX(' ', bar)-1),
w = SUBSTRING(bar, CHARINDEX(' ', bar)+1, LEN(bar)),
rn = ROW_NUMBER() OVER (ORDER BY bar)
FROM
@foo
),
split2 AS
(
SELECT
rn,
cat1 = LEFT(n, 2),
wl = RTRIM(SUBSTRING(w, 1,
COALESCE(NULLIF(CHARINDEX('|', w), 0)-1, LEN(w)))),
wr = LTRIM(SUBSTRING(w, NULLIF(CHARINDEX('|', w),0) + 1, LEN(w))),
cat2 = NULLIF(SUBSTRING(n, 4, 2), ''),
cat3 = NULLIF(SUBSTRING(n, 7, 2), '')
FROM
split1
),
split3 AS
(
SELECT
rn,
cat1descr = wl,
cat2descr = RTRIM(SUBSTRING(wr, 1,
COALESCE(NULLIF(CHARINDEX('|', wr), 0)-1, LEN(wr)))),
cat3descr = LTRIM(SUBSTRING(wr,
NULLIF(CHARINDEX('|', wr),0) + 1, LEN(wr)))
FROM
split2
)
SELECT
s2.cat1, s3.cat1descr,
s2.cat2, s3.cat2descr,
s2.cat3, s3.cat3descr
FROM split2 AS s2
INNER JOIN split3 AS s3
ON s2.rn = s3.rn;
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