如何加快与子进程的通信
问题描述
我正在使用带有 threading
线程的 Python 2 subprocess
来获取标准输入,并使用二进制文件 A
、B
和 C
并将修改后的数据写入标准输出.
I am using Python 2 subprocess
with threading
threads to take standard input, process it with binaries A
, B
, and C
and write modified data to standard output.
这个脚本(我们称之为:A_to_C.py
)非常慢,我想学习如何修复它.
This script (let's call it: A_to_C.py
) is very slow and I'd like to learn how to fix it.
大致流程如下:
A_process = subprocess.Popen(['A', '-'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
produce_A_thread = threading.Thread(target=produceA, args=(sys.stdin, A_process.stdin))
B_process = subprocess.Popen(['B', '-'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
convert_A_to_B_thread = threading.Thread(target=produceB, args=(A_process.stdout, B_process.stdin))
C_process = subprocess.Popen(['C', '-'], stdin=subprocess.PIPE)
convert_B_to_C_thread = threading.Thread(target=produceC, args=(B_process.stdout, C_process.stdin))
produce_A_thread.start()
convert_A_to_B_thread.start()
convert_B_to_C_thread.start()
produce_A_thread.join()
convert_A_to_B_thread.join()
convert_B_to_C_thread.join()
A_process.wait()
B_process.wait()
C_process.wait()
这个想法是标准输入进入A_to_C.py
:
The idea is that standard input goes into A_to_C.py
:
A
二进制文件处理一大块标准输入,并使用函数produceA
创建A
输出.B
二进制文件处理A
的标准输出块并通过produceB
函数创建B
输出代码>.C
二进制文件通过produceC
函数处理B
的标准输出块并写入C
- 输出到标准输出.
- The
A
binary processes a chunk of standard input and createsA
-output with the functionproduceA
. - The
B
binary processes a chunk ofA
's standard output and createsB
-output via the functionproduceB
. - The
C
binary processes a chunk ofB
's standard output via the functionproduceC
and writesC
-output to standard output.
我使用 cProfile 进行了分析,并且该脚本中的几乎所有时间似乎都花在了获取线程锁上.
I did profiling with cProfile and nearly all of the time in this script appears to be spent in acquiring thread locks.
例如,在测试 417s 作业中,416s(>99% 的总运行时间)用于获取线程锁:
For instance, in a test 417s job, 416s (>99% of the total runtime) is spent on acquiring thread locks:
$ python
Python 2.6.6 (r266:84292, Nov 21 2013, 10:50:32)
[GCC 4.4.7 20120313 (Red Hat 4.4.7-4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import pstats
>>> p = pstats.Stats('1.profile')
>>> p.sort_stats('cumulative').print_stats(10)
Thu Jun 12 22:19:07 2014 1.profile
1755 function calls (1752 primitive calls) in 417.203 CPU seconds
Ordered by: cumulative time
List reduced from 162 to 10 due to restriction <10>
ncalls tottime percall cumtime percall filename:lineno(function)
1 0.020 0.020 417.203 417.203 A_to_C.py:90(<module>)
1 0.000 0.000 417.123 417.123 A_to_C.py:809(main)
6 0.000 0.000 416.424 69.404 /foo/python/2.7.3/lib/python2.7/threading.py:234(wait)
32 416.424 13.013 416.424 13.013 {method 'acquire' of 'thread.lock' objects}
3 0.000 0.000 416.422 138.807 /foo/python/2.7.3/lib/python2.7/threading.py:648(join)
3 0.000 0.000 0.498 0.166 A_to_C.py:473(which)
37 0.000 0.000 0.498 0.013 A_to_C.py:475(is_exe)
3 0.496 0.165 0.496 0.165 {posix.access}
6 0.000 0.000 0.194 0.032 /foo/python/2.7.3/lib/python2.7/subprocess.py:475(_eintr_retry_call)
3 0.000 0.000 0.191 0.064 /foo/python/2.7.3/lib/python2.7/subprocess.py:1286(wait)
我的 threading.Thread
和/或 subprocess.Popen
安排有什么问题导致此问题?
What am I doing wrong with my threading.Thread
and/or subprocess.Popen
arrangement which is causing this issue?
解决方案
您对 subprocess.Popen() 的调用隐式指定了 bufsize 的默认值 0,这会强制无缓冲 I/O.尝试添加一个合理的缓冲区大小(4K、16K,甚至 1M),看看是否有什么不同.
Your calls to subprocess.Popen() implicitly specify the default value of bufsize, 0, which forces unbuffered I/O. Try adding a reasonable buffer size (4K, 16K, even 1M) and see if it makes any difference.
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