如何生成随机 Base36 ID
有没有办法生成随机base36 标识符SQL Server 中定义的字符数?
Is there a way of generating random base36 identifiers with a defined character count in SQL Server?
我搜索并发现了许多将 base 36 转换为 int 以及将其转换为 int 的示例,但不是用于随机生成唯一 ID 的示例.
I have searched and found many examples of converting base 36 to int and vice versa, but not for randomly generating unique IDs.
推荐答案
这个解决方案有点冗长但有效并且可以轻松适应各种需求.以下是一些示例输出:
This solution a bit verbose but works and can easily be adapted to a variety of requirements. Here's some sample output:
aapx0k k4fdbb vzbl5x
8vr1bs gbix1q g5kctv
he6e50 m9j0m0 2vz53l
yw72hs hgbo5h 3oen9v
6t4q75 337670 5sf3h4
yqr35s xoh4hh tc0wtf
w7trkj lnnpdk zk2ln1
1gt7qr l6m72n ja5kvm
kg6f9y 6t3b7a ujfr0i
2jatgo 0yv8rv wvbjfa
请注意,您需要创建一个视图来包装 UDF 中不允许使用的 RAND.所以这个解决方案需要两个 db 对象,一个视图和一个 udf.
Note that you need to create a view to wrap the use of RAND which is not allowed inside a UDF. So this solution needs two db objects, a view and a udf.
CREATE VIEW ViewRandInt AS (SELECT RAND() * 36 as RandInt)
GO
CREATE FUNCTION GetRandomBase36Id
(
@charCount AS INT
)
RETURNS VARCHAR(50) AS BEGIN
DECLARE @characters CHAR(36),
@result VARCHAR(MAX),
@counter INT,
@randNum INT
SELECT @characters = '0123456789abcdefghijklmnopqrstuvwxyz',
@result = '',
@counter = 0;
WHILE @counter < @charCount
BEGIN
SELECT @randNum = RandInt FROM ViewRandInt
SET @result = @result + SUBSTRING(@characters, @randNum+1, 1)
SET @counter = @counter + 1
END
RETURN @result;
END
-- Test:
SELECT dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
, dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6), dbo.GetRandomBase36Id(6)
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