在SSIS脚本任务中激活特定Excel工作表
我有一个脚本任务,它打开一个Excel文件并将其另存为.csv,但它会保存与该文件一起打开的工作表,而我想选择将哪个工作表另存为.csv,这是我当前使用的脚本:
Public Sub Main()
Dim oMissing As Object = System.Reflection.Missing.Value
Dim xl As New Microsoft.Office.Interop.Excel.ApplicationClass()
Dim xlBook As Microsoft.Office.Interop.Excel.Workbook
Dim xlSheet As Microsoft.Office.Interop.Excel.Worksheet
Dim laPath As String = "C:Filename.xlsx"
xlBook = DirectCast(xl.Workbooks.Open(laPath, oMissing, oMissing, oMissing, oMissing, oMissing,
oMissing, oMissing, oMissing, oMissing, oMissing, oMissing,
oMissing, oMissing, oMissing), Workbook)
xl.DisplayAlerts = False
xlSheet = DirectCast(xlBook.Worksheets.Item(1), Worksheet)
xlBook.SaveAs("C:Filename.csv", 6, oMissing, oMissing, oMissing, oMissing,, oMissing, oMissing, oMissing, oMissing, oMissing)
xl.Application.Workbooks.Close()
Dts.TaskResult = ScriptResults.Success
End Sub
我想我必须使用xlbook.Worksheets("Sheet1").Activate
,但我似乎找不到它。
解决方案
您必须按工作表的名称打开它,然后使用Select()
函数选择它:
xlSheet = xlBook.Worksheets("Sheet1")
xlSheet.Select()
您的代码将如下所示:
Public Sub Main()
Dim oMissing As Object = System.Reflection.Missing.Value
Dim xl As New Microsoft.Office.Interop.Excel.ApplicationClass()
Dim xlBook As Microsoft.Office.Interop.Excel.Workbook
Dim xlSheet As Microsoft.Office.Interop.Excel.Worksheet
Dim laPath As String = "C:Filename.xlsx"
xlBook = xl.Workbooks.Open(laPath)
xl.DisplayAlerts = False
xlSheet = xlBook.Worksheets("Sheet1")
xlSheet.Select()
xlBook.SaveAs("C:Filename.csv", Excel.XlFileFormat.xlCSV,Excel.XlSaveAsAccessMode.xlNoChange)
xl.Application.Workbooks.Close()
Dts.TaskResult = ScriptResults.Success
End Sub
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