运算符重载矩阵乘法

我遇到的问题是如何为K的最内层循环获取正确的列数。 一个例子是2x3矩阵和3x2矩阵相乘。 结果应该是2x2矩阵，但目前我不知道如何将2的值发送给运算符重载函数。 应该是 Int k=0；k<；第一个矩阵的列；k++

  Matrix::Matrix(int row, int col)
   {
    rows = row;
    cols = col;
    cx = (float**)malloc(rows * sizeof(float*));  //initialize pointer to pointer matrix
   for (int i = 0; i < rows; i++)
      *(cx + i) = (float*)malloc(cols * sizeof(float));
    }



Matrix Matrix::operator * (Matrix dx)
 {
   Matrix mult(rows, cols);
    for (int i = 0; i < rows; i++)
     { 
       for (int j = 0; j < cols; j++)
        {
            mult.cx[i][j] = 0;
           for (int k = 0; k < ?;k++) //?????????????
            {
                 mult.cx[i][j] += cx[i][k] * dx.cx[k][j];
            }
        }
    }
      mult.print();
      return mult;


 //calling
  Matrix mult(rowA, colB);
           mult = mat1 * mat2;
}

---

解决方案

线性代数规则规定结果的维度应为行x dx.cols

    Matrix Matrix::operator * (Matrix dx)
    {
     Matrix mult(rows, dx.cols);
    for (int i = 0; i < rows; i++)
     { 
       for (int j = 0; j < cols; j++)
        {
            mult.cx[i][j] = 0;
           for (int k = 0; k < cols;k++) //?????????????
            {
                 mult.cx[i][j] += cx[i][k] * dx.cx[k][j];
            }
        }
    }
      mult.print();
      return mult;