如何在 Windows 中使用子进程
问题描述
我正在尝试将结果或函数 runcmd 保存在变量 Result 中.这是我尝试过的:导入子流程
I am trying to save the result or function runcmd in the variable Result. Here is what I have tried: import subprocess
def runcmd(cmd):
x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
Result = x.communicate(stdout)
return Result
runcmd("dir")
当我运行这些代码时,我得到了这个结果:
When I run ths code, I get this result:
Traceback (most recent call last):
File "C:Python27MyPythonMyCode.py", line 7, in <module>
runcmd("dir")
File "C:Python27MyPythonMyCode.py", line 4, in runcmd
x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
File "C:Python27libsubprocess.py", line 679, in __init__
errread, errwrite)
File "C:Python27libsubprocess.py", line 893, in _execute_child
startupinfo)
WindowsError: [Error 2] The system cannot find the file specified
我能做些什么来解决这个问题?
What could I do to fix this?
解决方案
我想你要找的是 os.listdir()
I think what you are looking for is os.listdir()
查看 os 模块了解更多信息
一个例子:
>>> import os
>>> l = os.listdir()
>>> print (l)
['DLLs', 'Doc', 'google-python-exercises', 'include', 'Lib', 'libs', 'LICENSE.txt', 'NEWS.txt', 'python.exe', 'pythonw.e
xe', 'README.txt', 'tcl', 'Tools', 'VS2010Cmd.lnk']
>>>
您也可以将输出读入列表:
You could also read the output into a list:
result = []
process = subprocess.Popen('dir',
shell=True,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE )
for line in process.stdout:
result.append(line)
errcode = process.returncode
for line in result:
print(line)
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