如何追查“双重免费或腐败"?错误

2022-01-31 00:00:00 debugging c c++ free

当我运行我的 (C++) 程序时,它会因此错误而崩溃.

When I run my (C++) program it crashes with this error.

* 检测到 glibc * ./load: 双重释放或损坏 (!prev):0x0000000000c6ed50 ***

* glibc detected * ./load: double free or corruption (!prev): 0x0000000000c6ed50 ***

如何追踪错误?

我尝试使用 print (std::cout) 语句,但没有成功.gdb 可以让这更容易吗?

I tried using print (std::cout) statements, without success. Could gdb make this easier?

推荐答案

如果你使用的是 glibc,你可以将 MALLOC_CHECK_ 环境变量设置为 2,这样会导致 glibc 使用 malloc 的容错版本,这将导致您的程序在完成双重释放时中止.

If you're using glibc, you can set the MALLOC_CHECK_ environment variable to 2, this will cause glibc to use an error tolerant version of malloc, which will cause your program to abort at the point where the double free is done.

您可以在运行程序之前使用 set environment MALLOC_CHECK_ 2 命令从 gdb 设置它;程序应该中止,free() 调用在回溯中可见.

You can set this from gdb by using the set environment MALLOC_CHECK_ 2 command before running your program; the program should abort, with the free() call visible in the backtrace.

请参阅 手册页以了解 malloc()更多信息

see the man page for malloc() for more information

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