C++20 constexpr 容器将如何工作?
作为 constexpr std::字符串
和constexpr std::vector
已被 C++20 接受,这些将如何使用?链接的论文在细节上非常短.我们是否需要指定特殊的 constexpr
分配器,使编译时字符串/向量与其正常等效项不兼容?
As constexpr std::string
and constexpr std::vector
have been accepted into C++20, how will these be used? The linked papers are very short on details. Do we need to specify special constexpr
allocators, making compile-time strings/vectors incompatible with their normal equivalents?
推荐答案
这两篇论文严重依赖P0784,其中讨论了编译时分配的工作方式.
Those two papers depend heavily on P0784, which discusses how allocations at compile-time will work.
不完整的答案:
- 只有
std::allocator
可以工作. - 所有分配都会被跟踪,并且必须在编译完成之前解除分配.这意味着您可以在编译时进行操作,但不能初始化
string
和vector
变量以在运行时使用.(就我个人而言,我认为这个限制很有可能会在标准的未来版本中取消 - 但这只是我的看法.)
- Only
std::allocator
will work. - All allocations are tracked, and must be deallocated before compilation is complete. This means that you can do manipulations at compile-time, but you can't initialize
string
andvector
variables to be used at run-time. (Personally, I think there's a good chance that this restriction will be lifted in a future version of the standard - but that's just my opinion.)
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