为什么在 C++ 中的容器中存储引用(不是指针)不起作用?
在我的程序中，我设置了一个 STL.
In my program I have a STL set.
set<string> myStrings;
为了提高我的代码效率，我将其更改为仅保留指针.(我不需要存储实际的字符串副本.)
To improve the efficiency of my code I changed it to hold, only pointers. (I don't need actual string copies to be stored.)
set<string*> myStrings;
我已经读到，尽可能用引用替换指针是一种很好的做法.(当然，仅当不需要指针的实际功能时.)
I have read that it is a good practice to substitute pointers with references when possible. (Of course, only if the actual functionality of a pointer is not needed.)
set<string&> myStrings;
不过，后者给了我很多编译器错误.为什么不能使用引用作为容器元素?
The latter one gives me a lot of compiler errors, though. Why is it not possible to use references as container elements?
推荐答案
容器存储对象.引用不是对象.
Containers store objects. References are not objects.
C++11 规范明确规定(§23.2.1[container.requirements.general]/1):
The C++11 specification clearly states (§23.2.1[container.requirements.general]/1):
容器是存储其他对象的对象.
Containers are objects that store other objects.
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