为什么在 C++ 中的容器中存储引用(不是指针)不起作用?

2022-01-24 00:00:00 reference containers c++ stl

在我的程序中,我设置了一个 STL.

In my program I have a STL set.

set<string> myStrings;

为了提高我的代码效率,我将其更改为仅保留指针.(我不需要存储实际的字符串副本.)

To improve the efficiency of my code I changed it to hold, only pointers. (I don't need actual string copies to be stored.)

set<string*> myStrings;

我已经读到,尽可能用引用替换指针是一种很好的做法.(当然,仅当不需要指针的实际功能时.)

I have read that it is a good practice to substitute pointers with references when possible. (Of course, only if the actual functionality of a pointer is not needed.)

set<string&> myStrings;

不过,后者给了我很多编译器错误.为什么不能使用引用作为容器元素?

The latter one gives me a lot of compiler errors, though. Why is it not possible to use references as container elements?

推荐答案

容器存储对象.引用不是对象.

Containers store objects. References are not objects.

C++11 规范明确规定(§23.2.1[container.requirements.general]/1):

The C++11 specification clearly states (§23.2.1[container.requirements.general]/1):

容器是存储其他对象的对象.

Containers are objects that store other objects.

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