c - 这个 2 const 是什么意思?
代码:
const char * const key;
上面的指针有2个const,我第一次看到这样的东西.
There are 2 const in above pointer, I saw things like this the first time.
我知道第一个 const 使指针指向的值不可变,但是第二个 const 是否使指针本身不可变?
I know the first const makes the value pointed by the pointer immutable, but did the second const make the pointer itself immutable?
谁能帮忙解释一下?
@更新:
我写了一个程序来证明答案是正确的.
And I wrote a program that proved the answer is correct.
#include <stdio.h>
void testNoConstPoiner() {
int i = 10;
int *pi = &i;
(*pi)++;
printf("%d
", i);
}
void testPreConstPoinerChangePointedValue() {
int i = 10;
const int *pi = &i;
// this line will compile error
// (*pi)++;
printf("%d
", *pi);
}
void testPreConstPoinerChangePointer() {
int i = 10;
int j = 20;
const int *pi = &i;
pi = &j;
printf("%d
", *pi);
}
void testAfterConstPoinerChangePointedValue() {
int i = 10;
int * const pi = &i;
(*pi)++;
printf("%d
", *pi);
}
void testAfterConstPoinerChangePointer() {
int i = 10;
int j = 20;
int * const pi = &i;
// this line will compile error
// pi = &j
printf("%d
", *pi);
}
void testDoublePoiner() {
int i = 10;
int j = 20;
const int * const pi = &i;
// both of following 2 lines will compile error
// (*pi)++;
// pi = &j
printf("%d
", *pi);
}
int main(int argc, char * argv[]) {
testNoConstPoiner();
testPreConstPoinerChangePointedValue();
testPreConstPoinerChangePointer();
testAfterConstPoinerChangePointedValue();
testAfterConstPoinerChangePointer();
testDoublePoiner();
}
取消注释3个函数中的行,将得到编译错误提示.
Uncomment lines in 3 of the functions, will get compile error with tips.
推荐答案
第一个 const 告诉你不能改变 *key
, key[i]
等
First const tells you can not change *key
, key[i]
etc
以下行无效
*key = 'a';
*(key + 2) = 'b';
key[i] = 'c';
第二个常量告诉你不能改变key
Second const tells that you can not change key
以下行无效
key = newkey;
++key;
同时查看如何阅读这个复杂的声明
添加更多细节.
const char *key
:可以改变key,但不能改变key指向的字符.char *const key
:不能改变key,但可以改变key指向的字符const char *const key
:你不能改变key和pointer chars.
const char *key
: you can change key but can not change the chars pointed by key.char *const key
: You can not change key but can the chars pointed by keyconst char *const key
: You can not change the key as well as the pointer chars.
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