调用临时对象的方法是否安全?
我有一个返回 char* 的函数.由于我必须连接一些字符串，所以我写了以下行:
I have a function which shall return a char*. Since I have to concatenate some strings, I wrote the following line:
std::string other_text;
// ...
func(("text" + other_text).c_str());
我知道我可以避免命名我想使用的字符串的问题.我只是想借此机会提出一个更笼统的问题:调用临时变量的方法是否安全?是否符合标准?
I know that I could avoid the question naming the string I want to use. I just want to take the chance to make a more general question: is it safe to call methods of temporary variables? is it standard compliant?
推荐答案
调用临时变量的方法是安全的，但返回临时变量的char*供以后使用是不安全的.
It is safe to call methods of temporary variables, but not safe to return a char* of a temporary variable for later use.
这个 char* 指向一个即将被释放的缓冲区.一旦它被释放，你将有一个指向内存中无效区域的指针.
This char* points to a buffer that will be freed soon. Once it is freed you will have a pointer to an invalid region in memory.
请返回一个 std::string 对象.
Instead please return an std::string object.
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