从 demangled 名称中获取 mangled 名称
有什么办法可以从 g++ 中的 demangled name 中取回 mangled name.
Is there any way to get back the mangled name from demangled name in g++.
例如，我的名称是 func(char*, int)，我应该怎么做才能得到重整的名称，即 _Z4funcPci?
For example , I have the demangled name func(char*, int), what should I do to get the mangled name i.e _Z4funcPci back?
我的问题是特定于 g++ 的.
My question is g++ specific.
推荐答案
你可以简单地使用 g++ 编译一个带有你需要的签名的空函数并从中提取名称.例如:
You can simply use g++ to compile an empty function with the signature you require and extract the name from that. For example:
echo "int f1(char *, int) {} " | g++ -x c++ -S - -o- | grep "^_.*:$" | sed -e 's/:$//'
给出输出
_Z2f1Pci
这是我认为你需要的.确保包含任何相关的头文件，因为它们会影响符号被破坏的方式.
which is I think what you require. Make sure that you include any relevant header files as they will affect the way the symbols are mangled.
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