将每种类型包装在模板类中的可变参数模板中
给定一个可变参数模板 Types...
,我想为包中的每个类型存储 A<>
.这可以在 A<>
的元组中完成,但我需要以编程方式导出所述元组的类型.
Given a variadic template Types...
, I would like to store A<>
for each of the types in the pack. This could be done in a tuple of A<>
's, but I'd need to programmatically derive the type of said tuple.
在 c++11/14/17 中甚至可能发生这样的事情吗?
Is such a thing even possible in c++11/14/17?
template <class T> class A { };
template <class... Types>
class B
{
// A tuple of A<>'s for each type in Types...
std::tuple<A<Type1>, A<Type2>, ...> data;
};
推荐答案
只需:
template <class... Types>
class B
{
std::tuple<A<Types>...> data;
};
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