通过 'tuple' 和 'tie' 实现比较运算符，好主意吗?

^{(Note: tuple and tie can be taken from Boost or C++11.)}
When writing small structs with only two elements, I sometimes tend to choose a std::pair, as all important stuff is already done for that datatype, like operator< for strict-weak-ordering.
The downsides though are the pretty much useless variable names. Even if I myself created that typedef, I won't remember 2 days later what first and what second exactly was, especially if they are both of the same type. This gets even worse for more than two members, as nesting pairs pretty much sucks.
The other option for that is a tuple, either from Boost or C++11, but that doesn't really look any nicer and clearer. So I go back to writing the structs myself, including any needed comparision operators.
Since especially the operator< can be quite cumbersome, I thought of circumventing this whole mess by just relying on the operations defined for tuple:

operator< 示例，例如对于严格-弱排序:

bool operator<(MyStruct const& lhs, MyStruct const& rhs){
  return std::tie(lhs.one_member, lhs.another, lhs.yet_more) <
         std::tie(rhs.one_member, rhs.another, rhs.yet_more);
}