当另一个线程可能设置它(最多一次)时，可以读取共享布尔标志而不锁定它吗?

I would like my thread to shut down more gracefully so I am trying to implement a simple signalling mechanism. I don't think I want a fully event-driven thread so I have a worker with a method to graceully stop it using a critical section Monitor (equivalent to a C# lock I believe):

绘图线程.h

class DrawingThread {
    bool stopRequested;
    Runtime::Monitor CSMonitor;
    CPInfo *pPInfo;
    //More..
}

绘图线程.cpp

void DrawingThread::Run() {
    if (!stopRequested)
        //Time consuming call#1
    if (!stopRequested) {
        CSMonitor.Enter();
        pPInfo = new CPInfo(/**/);
        //Not time consuming but pPInfo must either be null or constructed. 
        CSMonitor.Exit();
    }
    if (!stopRequested) {
        pPInfo->foobar(/**/);//Time consuming and can be signalled
    }
    if (!stopRequested) {
        //One more optional but time consuming call.
    }
}


void DrawingThread::RequestStop() {
    CSMonitor.Enter();
    stopRequested = true;
    if (pPInfo) pPInfo->RequestStop();
    CSMonitor.Exit();
}

我了解(至少在 Windows 中)Monitor/lock 是最便宜的线程同步原语，但我希望避免过度使用.我应该包装这个布尔标志的每次读取吗?它被初始化为 false，并且仅在请求停止时设置一次为 true(如果在任务完成之前请求它).