如何从 C++ 中的函数返回结构?

2022-01-19 00:00:00 function return structure struct c++

我在几个不同的论坛上尝试过，似乎无法得到一个直接的答案，我怎样才能让这个函数返回结构?如果我尝试'return newStudent;'我收到错误消息不存在从 studentType 到 studentType 的合适的用户定义转换."

I've tried on a few different forums and can't seem to get a straight answer, how can I make this function return the struct? If I try 'return newStudent;' I get the error 'No suitable user-defined conversion from studentType to studentType exists.'

// Input function
studentType newStudent()
{   
    struct studentType
    {
        string studentID;
        string firstName;
        string lastName;
        string subjectName;
        string courseGrade;

        int arrayMarks[4];

        double avgMarks;

    } newStudent;

    cout << "
Please enter student information:
";

    cout << "
First Name: ";
    cin >> newStudent.firstName;

    cout << "
Last Name: ";
    cin >> newStudent.lastName;

    cout << "
Student ID: ";
    cin >> newStudent.studentID;

    cout << "
Subject Name: ";
    cin >> newStudent.subjectName;

    for (int i = 0; i < NO_OF_TEST; i++)
    {   cout << "
Test " << i+1 << " mark: ";
        cin >> newStudent.arrayMarks[i];
    }

    newStudent.avgMarks = calculate_avg(newStudent.arrayMarks,NO_OF_TEST );
    newStudent.courseGrade = calculate_grade (newStudent.avgMarks);

}

推荐答案

你的范围有问题.在函数之前定义结构体，而不是在函数内部.

You have a scope problem. Define the struct before the function, not inside it.

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