char * 到字符串文字如何有效?
所以从我的理解指针变量指向一个地址.那么，以下代码在 C++ 中如何有效?
So from my understanding pointer variables point to an address. So, how is the following code valid in C++?
char* b= "abcd"; //valid
int *c= 1; //invalid
推荐答案
在 C 和非常旧的 C++ 版本中，字符串文字 "abcd" 的类型为 char[]，一个字符数组.这样的数组自然会被 char* 指向，但不能被 int* 指向，因为那不是兼容的类型.
In C and very old versions of C++, a string literal "abcd" is of type char[], a character array. Such an array can naturally get pointed at by a char*, but not by a int* since that's not a compatible type.
但是，C 和 C++ 是不同的，通常是不兼容的编程语言.大约 20 年前，他们放弃了彼此的兼容性.
However, C and C++ are different, often incompatible programming languages. They dropped compatibility with each other some 20 years ago.
在标准 C++ 中，字符串文字的类型为 const char[]，因此您发布的代码在 C++ 中均无效.这不会编译:
In standard C++, a string literal is of type const char[] and therefore none of your posted code is valid in C++. This won't compile:
char* b = "abcd"; //invalid, discards const qualifier
这将:
const char* c = "abcd"; // valid
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