C++ 中的变量初始化

2022-01-18 00:00:00 initialization variables c++

我的理解是一个int变量会自动初始化为0;然而,事实并非如此.下面的代码打印一个随机值.

My understanding is that an int variable will be initialized to 0 automatically; however, it is not. The code below prints a random value.

int main () 
{   
    int a[10];
    int i;
    cout << i << endl;
    for(int i = 0; i < 10; i++)
        cout << a[i] << " ";
    return 0;
}

  • 哪些规则(如果有)适用于初始化?
  • 具体来说,在什么情况下变量会自动初始化?
  • 推荐答案

    if会自动初始化

    • 它是一个类/结构实例,其中默认构造函数初始化所有原始类型;比如 MyClass 实例;
    • 您使用数组初始值设定项语法,例如int a[10] = {}(全为零)或 int a[10] = {1,2};(除前两项外全为零:a[0] == 1a[1] == 2)
    • 同样适用于非聚合类/结构,例如我的类实例 = {};(有关这方面的更多信息,请参阅 这里)
    • 这是一个全局/外部变量
    • 变量是定义的static(无论是在函数内部还是在全局/命名空间范围内)-感谢 Jerry
    • it's a class/struct instance in which the default constructor initializes all primitive types; like MyClass instance;
    • you use array initializer syntax, e.g. int a[10] = {} (all zeroed) or int a[10] = {1,2}; (all zeroed except the first two items: a[0] == 1 and a[1] == 2)
    • same applies to non-aggregate classes/structs, e.g. MyClass instance = {}; (more information on this can be found here)
    • it's a global/extern variable
    • the variable is defined static (no matter if inside a function or in global/namespace scope) - thanks Jerry

    永远不要相信一个普通类型的变量(int、long、...)会自动初始化!它可能发生在像 C# 这样的语言中,但不会发生在 C &C++.

    Never trust on a variable of a plain type (int, long, ...) being automatically initialized! It might happen in languages like C#, but not in C & C++.

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