在初始化中使用新声明的变量(int x = x+1)?
我偶然发现了一个令我惊讶的行为:
I just stumbled upon a behavior which surprised me:
写作时:
int x = x+1;
在 C/C++ 程序(或涉及新创建的变量 x 的更复杂的表达式)中，我的 gcc/g++ 编译没有错误.在上述情况下，X 之后为 1.请注意，先前声明的范围内没有变量 x.
in a C/C++-program (or even more complex expression involving the newly created variable x) my gcc/g++ compiles without errors. In the above case X is 1 afterwards. Note that there is no variable x in scope by a previous declaration.
所以我想知道这是正确的行为(甚至在某些情况下可能有用)还是只是我的 gcc 版本或一般 gcc 的解析器特性.
So I'd like to know whether this is correct behaviour (and even might be useful in some situation) or just a parser pecularity with my gcc version or gcc in general.
顺便说一句:以下不起作用:
BTW: The following does not work:
int x++;
推荐答案
用表达式:
int x = x + 1;
变量 x 出现在 = 符号处，这就是您可以在右侧使用它的原因.开始存在"是指变量存在，但尚未被初始化部分赋值.
the variable x comes into existence at the = sign, which is why you can use it on the right hand side. By "comes into existence", I mean the variable exists but has yet to be assigned a value by the initialiser part.
但是，除非您正在初始化具有静态存储持续时间的变量(例如，在函数外部)，否则这是未定义的行为，因为存在的 x 具有任意值.
However, unless you're initialising a variable with static storage duration (e.g., outside of a function), it's undefined behaviour since the x that comes into existence has an arbitrary value.
C++03 有这样的说法:
C++03 has this to say:
名称的声明点紧接在其完整声明符之后(第 8 条)和初始化器之前(如果有的话)...
The point of declaration for a name is immediately after its complete declarator (clause 8) and before its initializer (if any) ...
示例:int x = 12;
<代码>{ int x = x;}
这里第二个 x 用它自己的(不确定的)值初始化.
Example:
int x = 12;
{ int x = x; }
Here the second x is initialized with its own (indeterminate) value.
第二种情况几乎就是您的问题.
That second case there is pretty much what you have in your question.
相关文章