根据“grid_location"，按钮有自己的坐标系.方法?

2022-01-18 00:00:00 python python-3.x tkinter grid

问题描述

我正在尝试使用 Tkinter 中 Grid Geometry Manager 中的 grid_location 方法，但似乎我做错了什么.

I'm trying to use the grid_location method, from the Grid Geometry Manager, in Tkinter, but it seems that I'm doing something wrong.

这是我的代码:

from tkinter import * 


root = Tk()

b=Button(root, text="00")
b.grid(row=0, column=0)
b2=Button(root, text="11")
b2.grid(row=1, column=1)
b3=Button(root, text="22")
b3.grid(row=2, column=2)
b4=Button(root, text="33")
b4.grid(row=3, column=3)
b5=Button(root, text="44")
b5.grid(row=4, column=4)

def mouse(event):
    print(event.x, event.y)
    print(root.grid_location(event.x, event.y))

root.bind("<Button-1>", mouse)

root.mainloop()

当我在按钮外部单击时，它可以工作，但是当我在任何按钮内部单击时，似乎每个按钮都有自己的坐标系.所以，每个按钮都在 (0, 0) 单元格上，尽管在代码中，它们都在规则网格上.

When I click outside the Buttons, it works, but when I click inside of any Button, it seems that each button has its own coordinate system. So, each button is on the (0, 0) cell, despite that in the code, they are on a regular grid.

解决方案

你说得对，每个按钮都有自己的坐标系".不过，更准确地说，event.x 和 event.y 值是相对于与事件关联的小部件而不是小部件的父窗口或根窗口.

You are correct that each button "has it's own coordinate system". More accurately, though, the event.x and event.y values are relative to the widget associated with the event rather than the widget's parent or the root window.

如果您确实需要小部件所在的行和列，可以使用 grid_info 来获取与事件关联的小部件的行和列.例如:

If you really do need the row and column that the widget is in you can use grid_info to get the row and column of the widget associated with the event. For example:

def mouse(event):
    grid_info = event.widget.grid_info()
    print("row:", grid_info["row"], "column:", grid_info["column"])

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