测试给定的数字是否为整数
我正在尝试实现用户定义的函数来测试数字是否为整数:
I am trying to implement user defined function which tests if a number is an integer:
#include <iostream>
#include <typeinfo>
using namespace std;
bool integer(float k){
if (k==20000) return false;;
if (k==(-20000)) return false;
if (k==0) return true;
if (k<0) return integer(k+1);
else if(k>0) return integer (k-1);
return false;
}
int main(){
float s=23.34;
float s1=45;
cout<<boolalpha;
cout<<integer(s)<<endl;
cout<<integer(s1)<<endl;
return 0;
}
所以这个想法是,如果一个数字是一个整数,不管它是负数还是正数,如果我们将它减一或加一,我们必须得到零,但问题是,我们怎么能为增加和减少创建上限和下限?
So the idea is that,if a number is an integer, does not matter if it is a negative or positive , if we decrease or increase it by one, we must get zero, but the problem is, that how can we create upper and lower bounds for increasing and decreasing?
推荐答案
#include <cmath>
bool is_integer(float k)
{
return std::floor(k) == k;
}
此解决方案应该适用于 k
的所有可能值.我很确定这是您可以使用 ==
安全地比较浮点数的情况.
This solution should work for all possible values of k
. I am pretty sure this is a case where you can safely compare floats using ==
.
尝试仔细命名函数.integer
并没有给出任何线索它实际上是什么,所以我把函数名改成了更有意义的名字.
Try to thoughtfully name functions. integer
does not give any clue what it actually does, so I changed the function name to something more meaningful.
对于未来,测试一个数字是否为整数应该感觉就像一个非常简单的操作,所以你应该有一种强烈的感觉,最好的解决方案将非常简单.我希望你意识到你原来的解决方案是荒谬的,原因有很多(最大的原因:它会在绝大多数情况下导致堆栈溢出).
For the future, testing if a number is integer should feel like a very simple operation, so you should have a strong feeling that the best solution will be very simple. I hope you realize your original solution is absurd for many reasons (biggest reason: it will cause a stack overflow for the vast majority of cases).
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