C不是运算符应用于int?
我有
int x = 5;
printf("%d", x); //i get 5... expected
x = !x;
printf("%d", x);// i get 0... hmm
5 二进制是:0101如果我们对每个位进行逆运算，我们应该得到 1010，但 ! 不一定是反相器，它是一个逻辑运算符.为什么我得到一个 0 ?
5 in binary is: 0101
if we apply the inverse to each bit, we should get 1010, but ! is not necessarily an inverter, it's a logical operator. Why do i get a 0 ?
是因为在 C 中，正数被视为真，所以 !-ing 它会导致 0?这个编译器是特定的吗?
is the reason that, in C, a positive number is treated as true and so !-ing it would result in 0?
is this compiler specific?
推荐答案
not (!) 运算符返回 0 或 1，分别取决于输入是非零还是 0.
The not (!) operator returns either 0 or 1, depending on whether the input is non-zero or 0 respectively.
如果您正在寻找按位否定，请尝试 ~x.
If you are looking for a bitwise negation, try ~x.
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