全局范围与全局命名空间
我看到了这两个短语的用法:全局作用域和全局命名空间.它们有什么区别?
I saw usages of these two phrases: global scope and global namespace. What is the difference between them?
推荐答案
在 C++ 中，每个名称都有其不存在的范围.范围可以通过多种方式定义:它可以通过 namespace、functions、classes 和 { }.
In C++, every name has its scope outside which it doesn't exist. A scope can be defined by many ways : it can be defined by namespace, functions, classes and just { }.
所以一个命名空间，无论是全局的还是其他的，都定义了一个范围.全局命名空间是指使用::，在这个命名空间中定义的符号被称为具有全局作用域.默认情况下，符号存在于全局命名空间中，除非它定义在以关键字 namespace 开头的块内，或者它是类的成员，或者是函数的局部变量:
So a namespace, global or otherwise, defines a scope. The global namespace refers to using ::, and the symbols defined in this namespace are said to have global scope. A symbol, by default, exists in a global namespace, unless it is defined inside a block starts with keyword namespace, or it is a member of a class, or a local variable of a function:
int a; //this a is defined in global namespace
//which means, its scope is global. It exists everywhere.
namespace N
{
int a; //it is defined in a non-global namespace called `N`
//outside N it doesn't exist.
}
void f()
{
int a; //its scope is the function itself.
//outside the function, a doesn't exist.
{
int a; //the curly braces defines this a's scope!
}
}
class A
{
int a; //its scope is the class itself.
//outside A, it doesn't exist.
};
还请注意，name 可以被命名空间、函数或类定义的内部范围隐藏.因此名称空间 N 内的名称 a 将名称 a 隐藏在全局名称空间中.同理，函数和类中的名称隐藏了全局命名空间中的名称.如果你遇到这种情况，那么你可以使用 ::a 来引用全局命名空间中定义的名称:
Also note that a name can be hidden by inner scope defined by either namespace, function, or class. So the name a inside namespace N hides the name a in the global namspace. In the same way, the name in the function and class hides the name in the global namespace. If you face such situation, then you can use ::a to refer to the name defined in the global namespace:
int a = 10;
namespace N
{
int a = 100;
void f()
{
int a = 1000;
std::cout << a << std::endl; //prints 1000
std::cout << N::a << std::endl; //prints 100
std::cout << ::a << std::endl; //prints 10
}
}
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