科学计数法 C++ 中的字符串到双重转换
我有一个数据库,里面装满了像下面这样的双精度数:
I've got a database filled up with doubles like the following one:
1.60000000000000000000000000000000000e+01
有人知道如何在 C++ 中将这样的数字转换为双精度数吗?
Does anybody know how to convert a number like that to a double in C++?
有没有一种标准"的方式来做这类事情?还是我必须推出自己的功能?
Is there a "standard" way to do this type of things? Or do I have to roll my own function?
现在我正在做这样的事情:
Right now I'm doing sth like this:
#include <string>
#include <sstream>
int main() {
std::string s("1.60000000000000000000000000000000000e+01");
std::istringstream iss(s);
double d;
iss >> d;
d += 10.303030;
std::cout << d << std::endl;
}
谢谢!
推荐答案
像这样?这将是C++"的做法......
Something like this? This would be the "C++" way of doing it...
#include <sstream>
using namespace std;
// ...
string s = "1.60000000000000000000000000000000000e+01";
istringstream os(s);
double d;
os >> d;
cout << d << endl;
打印 16.
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