乘以 1.0 和 int 到浮点转换的精度
假设条件 (int)(i * 1.0f) == i 对于任何整数 i 为真是否安全?
Is it safe to assume that the condition (int)(i * 1.0f) == i is true for any integer i?
推荐答案
没有.
如果 i 足够大以至于 int(float(i)) != i (假设 float 是 IEEE-754 单精度，i = 0x1000001 足以证明这一点)那么这是错误的，因为乘以 1.0f 会强制转换为 float，即使随后的乘法不会改变值.
If i is sufficiently large that int(float(i)) != i (assuming float is IEEE-754 single precision, i = 0x1000001 suffices to exhibit this) then this is false, because multiplication by 1.0f forces a conversion to float, which changes the value even though the subsequent multiplication does not.
但是，如果 i 是一个 32 位整数并且 double 是 IEEE-754 double，那么 是真的 int(i*1.0) == i.
However, if i is a 32-bit integer and double is IEEE-754 double, then it is true that int(i*1.0) == i.
为了完全清楚，乘以 1.0f 是准确的.可能不是从 int 到 float 的转换.
Just to be totally clear, multiplication by 1.0f is exact. It's the conversion from int to float that may not be.
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