使用 std::string 构造函数复制 const char *

2022-01-12 00:00:00 string char c++ std

这段代码可以吗?

void SomeClass :: foo(const char * _name) {
     //name is of type const char *
     name = std::string(_name).c_str();
}

看起来它正在工作，但我不确定它是否正常

it looks like it is working, but iam not sure if it is ok

我应该做一个老式的 strcpy 吗?

should i do an old school strcpy ?

推荐答案

没关系，因为它可以编译并且不会导致未定义的行为.

It's ok since it compiles and doesn't cause undefined behavior.

不没问题，因为 name 在语句执行完成后指向无效内存.

It's not ok since name points to an invalid memory after the statement completes execution.

name = std::string(_name).c_str();

在这个语句的最后，临时的 std::string 被销毁，它释放了 c_str() 的内存.

At the end of this statement the temporary std::string is destroyed and it frees the memory of c_str().

我应该做一个老式的 strcpy 吗?

should i do an old school strcpy ?

不，只需将名称更改为 std::string:

No, just change name to be std::string:

void SomeClass :: foo(const char * _name) {
     //name is of type std::string
     name = _name;
}

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