如何在 C++ 中将字符串转换为 char 数组?

2022-01-12 00:00:00 string type-conversion c++

我想将 string 转换为 char 数组，而不是 char*.我知道如何将字符串转换为 char* (通过使用 malloc 或我在代码中发布的方式)――但这不是我想要的.我只是想将 string 转换为 char[size] 数组.有可能吗?

I would like to convert string to char array but not char*. I know how to convert string to char* (by using malloc or the way I posted it in my code) - but that's not what I want. I simply want to convert string to char[size] array. Is it possible?

#include <iostream>
#include <string>
#include <stdio.h>
using namespace std;

int main()
{
    // char to string
    char tab[4];
    tab[0] = 'c';
    tab[1] = 'a';
    tab[2] = 't';
    tab[3] = '';
    string tmp(tab);
    cout << tmp << "
";

    // string to char* - but thats not what I want

    char *c = const_cast<char*>(tmp.c_str());
    cout << c << "
";

    //string to char
    char tab2[1024];
    // ?

    return 0;
}

推荐答案

我能想到的最简单的方法是:

Simplest way I can think of doing it is:

string temp = "cat";
char tab2[1024];
strcpy(tab2, temp.c_str());

为了安全起见，您可能更喜欢:

For safety, you might prefer:

string temp = "cat";
char tab2[1024];
strncpy(tab2, temp.c_str(), sizeof(tab2));
tab2[sizeof(tab2) - 1] = 0;

或者可能是这种方式:

string temp = "cat";
char * tab2 = new char [temp.length()+1];
strcpy (tab2, temp.c_str());

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