使用函数从 C++ 中的数组中删除重复项
我正在编写一个程序,该程序将用户输入整数到一个数组中,调用一个从该数组中删除重复项的函数,然后打印出修改后的数组.当我运行它时,它允许我将值输入到数组中,但是当我完成输入值时会给我一个分段错误"错误消息.我做错了什么?
I'm writing a program that has a user input integers into an array, calls a function that removes duplicates from that array, and then prints out the modified array. When I run it, it lets me input values into the array, but then gives me a "Segmentation fault" error message when I'm done inputing values. What am I doing wrong?
这是我的代码:
#include <iostream>
using namespace std;
void rmDup(int array[], int& size)
{
for (int i = 0; i < size; i++)
{
for (int j = i + 1; j < size; j++)
{
if (array[i] == array[j])
{
array[i - 1 ] = array[i];
size--;
}
}
}
}
int main()
{
const int CAPACITY = 100;
int values[CAPACITY], currentSize = 0, input;
cout << "Please enter a series of up to 100 integers. Press 'q' to quit. ";
while (cin >> input)
{
if (currentSize < CAPACITY)
{
values[currentSize] = input;
currentSize++;
}
}
rmDup(values, currentSize);
for (int k = 0; k < currentSize; k++)
{
cout << values[k];
}
return 0;
}
谢谢.
推荐答案
for (int i = 0; i < size; i++)
{
for (int j = i + 1; j < size; j++)
{
if (array[i] == array[j])
{
array[i - 1 ] = array[i]; /* WRONG! array[-1] = something */
size--;
}
}
}
如果array[0]
和array[1]
相等,array[0-1] = array[0]
,意思是array[-1] = array[0]
.你不应该访问 array[-1]
.
If array[0]
and array[1]
are equal, array[0-1] = array[0]
, meaning that array[-1] = array[0]
. You are not supposed to access array[-1]
.
相关文章