如何在 MFC 应用程序中获取命令行参数?
我希望有一个基于对话框的小应用程序，它通过命令行参数传递，因此，我使用 VC++6 运行应用程序向导并选择了一个 MFC 对话框应用程序.
I wish to have a small dialog based application which is passed command line parameters, so, using VC++6 I ran the application wizard and chose an MFC dialog application.
这不会自动配备命令行参数.所以我去了到 MSDN 来刷新我对这些的记忆.MSDN 声明所有 C++ 程序具有 main() 或 wmain() 函数以及 argc 等参数到这里.我刚刚创建的应用程序没有这些.
This is not automatically equipped with command-line parameters. So I went to MSDN to refresh my memory on these. MSDN states that all C++ programs have either a main() or a wmain() function and that the argc, etc. arguments go here. The application I just created does not have these.
显然有一个函数是应用程序的入口点，可以我在这里坚持论点?我确实尝试过，但我不相信我实际上是在编辑正确的功能.(我能找到那个函数吗?是作为项目设置中的 main() 函数还是类似函数?)
As there is obviously a function which is the entry point to the application, can I stick the arguments here? I did try this, but I am not convinced that I was actually editing the correct function. (Can I find the function which is acting as the main() function from the project settings or similar?)
基本上，我如何让我的程序读取命令行参数.
Basically, how do I get my program to read command line parameters.
也可以作为副业.对于一个简单的程序，这是，我真的不想使它成为一个 MFC 应用程序，因此大小超过 MB.是否有允许我制作非 MFC 对话框的应用程序向导模板库申请?
Also as a sideline. For a simple program, which this is, I really do not want to make it an MFC application, and thereby over a MB in size. Are there application wizard template libraries that will allow me to make a non-MFC dialog application?
推荐答案
使用 GetCommandLine()，返回正在执行的文件名，后跟参数.
Use GetCommandLine(), which returns the name of the file being executed, followed by the arguments.
应用程序成员 m_lpCmdLine(像 yourApp.m_lpCmdLine 一样使用)仅包含参数.
The application member m_lpCmdLine (used like yourApp.m_lpCmdLine) contains only the arguments.
还有CWinApp::ParseCommandLine() 你可能会觉得有用.
There is also CWinApp::ParseCommandLine() that you may find useful.
还可以尝试使用 ATL COM 向导来创建非 MFC 对话框应用程序(选择 .exe 选项，而不是 .dll).
Also try the ATL COM wizard to create a non-MFC dialog application (chose the .exe option, not .dll).
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