在 MFC 中检测模态对话框
如何以编程方式检测我的 MFC 应用程序当前是否正在显示模式对话框或属性表?目前我正在使用以下,但我觉得代码也会触发无模式对话框.
How can I programmatically detect if my MFC application currently is displaying a modal dialog or property sheet? Currently I'm using the following, but I feel that the code also triggers for modeless dialogs.
bool HasModalDialog(const CWnd* pWnd)
{
const CWnd* pChildWnd = pWnd ? pWnd->GetNextWindow(GW_HWNDPREV) : NULL;
while (pChildWnd)
{
if (pWnd == pChildWnd->GetTopLevelParent() &&
(pChildWnd->IsKindOf(RUNTIME_CLASS(CDialog)) ||
pChildWnd->IsKindOf(RUNTIME_CLASS(CPropertySheet))))
{
return true;
}
pChildWnd = pChildWnd->GetNextWindow(GW_HWNDPREV);
}
return false;
}
用法:
HasModalDialog(AfxGetMainWnd())
谁有检测模态对话框的替代方法?
Anyone got a alternative way of detecting modal dialogs?
推荐答案
你试过了吗CWnd::GetLastActivePopup
?
我还没有测试过它是否只适用于模式对话框.
I haven't tested this to see if it'll work for modal dialogs only.
编辑 1: 根据 Raymond Chen,GetLastActivePopup
应该返回当前活动的模态对话框.
Edit 1: According to Raymond Chen, GetLastActivePopup
should return the current active modal dialog.
编辑 2: 检索当前模式窗口的另一种方法可能是修改代码以检查禁用的父/所有者 - 模式对话框应始终 在显示前禁用其所有者.
Edit 2: Perhaps another method to retrieve the current modal window would be to modify your code to check for a disabled parent/owner - modal dialogs should always disable their owner before displaying.
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