获取当前类的 typedef

2022-01-11 00:00:00 macros compiler-construction c++ typedef

我目前正在将 boost::intrusive_ptr 与我的 GUI 类一起使用.尽管这或多或少是一个方便的问题，但是否有正确的方法来获取当前类的类型名?我问的原因是我有一个宏来定义不同的指针类型:

I'm currently using boost::intrusive_ptr together with my GUI classes. Although this is more or less a convenience question, is there a proper way to get the typename of the current class? The reason I'm asking is that I have a macro for typedef'ing the different pointer types:

#define INTRUSIVE_PTR_TYPEDEFS(CLASSNAME) typedef boost::intrusive_ptr<CLASSNAME> Ptr; 
typedef boost::intrusive_ptr<const CLASSNAME> CPtr; 
typedef CLASSNAME* WeakPtr; 
typedef const CLASSNAME* CWeakPtr;

...

class Widget
{
public:
    INTRUSIVE_PTR_TYPEDEFS(Widget);
    ...
};

class Button : public Widget
{
public:
    INTRUSIVE_PTR_TYPEDEFS(Button);
    ...
};

自动推导出 CLASSNAME 会更舒服，因此您可以简单地将其复制粘贴"到类主体中.我使用的是 Visual Studio 2010 附带的编译器.

It would be much more comfortable to have CLASSNAME automatically deduced so you could simply copy'n'paste it into the class body. I'm using the compiler shipped with Visual Studio 2010.

提前致谢！

推荐答案

不，这在 C++ 中是不可能的.

No, that's not possible to do in C++.

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