Visual Studio 中的模板化函数指针数组

Guillaume Racicot gave an excellent answer to this question on how I could specialize template variables. But I'm having trouble in visual-studio-2017 with creating a templated array of function pointers. This code for example:

struct vec
{
    double x;
    double y;
    double z;
};

namespace details
{
template <typename T>
constexpr double X(const T& param) { return param.x; }

template <typename T>
constexpr double Y(const T& param) { return param.y; }

template <typename T>
constexpr double Z(const T& param) { return param.z; }
}

template <typename T, typename = void>
constexpr double (*my_temp[])(const vec&) = { &details::X<T>, &details::Y<T> };

template <typename T>
constexpr double (*my_temp<T, enable_if_t<is_floating_point_v<decltype(details::X(T()))>>>[])(const vec&) = { &details::X<T>, &details::Y<T>, &details::Z<T> };


int main() {
    vec foo = { 1.0, 2.0, 3.0 };

    for(const auto i : my_temp<decltype(foo)>) {
        cout << (*i)(foo) << endl;
    }
}

在 gcc 输出中:

1
2
3

template<typename T>
using fptr = auto(*)(T const&) -> double;

template <typename T, typename = void>
constexpr fptr<T> my_temp[] = {
    &details::X<T>, &details::Y<T>
};

template <typename T>
constexpr fptr<T> my_temp<T, enable_if_t<is_floating_point_v<decltype(details::X(T()))>>>[] = {
    &details::X<T>, &details::Y<T>, &details::Z<T>
};

template <typename T, typename = void>
constexpr std::array my_temp = {
    &details::X<T>, &details::Y<T>
};

template <typename T>
constexpr std::array my_temp<T, enable_if_t<is_floating_point<decltype(details::X(T()))>::value>> = {
    &details::X<T>, &details::Y<T>, &details::Z<T>
};

+------------+-------+-------+-------+
| Compiling? |  GCC  | Clang | MSVC  |
+------------+-------+-------+-------+
| raw array  |  Yes  |  ICE  |  No   |
+------------+-------+-------+-------+
| fptr alias |  Yes  |  ICE  |  Yes  |
+------------+-------+-------+-------+
| std::array |  Yes  |  Yes  |  Yes  |
+------------+-------+-------+-------+