为什么没有 C++ 的 DELETE 宏的原因

2022-01-11 00:00:00 pointers memory-management macros c++

是否有任何好的理由(也许宏是邪恶的"除外)不使用以下宏?

Are there any good reasons (except "macros are evil", maybe) NOT to use the following macros ?

#define DELETE( ptr ) 
if (ptr != NULL)      
{                     
    delete ptr;       
    ptr = NULL;       
}

#define DELETE_TABLE( ptr ) 
if (ptr != NULL)            
{                           
    delete[] ptr;           
    ptr = NULL;             
}

推荐答案

个人比较喜欢下面的

template< class T > void SafeDelete( T*& pVal )
{
    delete pVal;
    pVal = NULL;
}

template< class T > void SafeDeleteArray( T*& pVal )
{
    delete[] pVal;
    pVal = NULL;
}

它们最终编译成完全相同的代码.

They compile down to EXACTLY the same code in the end.

可能有一些奇怪的方法可以打破#define 系统,但就个人而言(这可能会让我感到痛苦;)我认为这不是什么大问题.

There may be some odd way you can break the #define system but, personally (And this is probably going to get me groaned ;) I don't think its much of a problem.

相关文章