如何强制包含“未使用的"?库中的对象定义

My question is similar to these but doesn't seem to correlate exactly:

如何在链接到可执行文件时强制将目标文件包含在静态库中?

强制使用 MSVC 导出符号

我得到的是这样的:

struct thingy;
struct container
{
  static container& instance(); // singleton

  int register_thingy(thingy*);
};

struct thingy
{
  virtual ~thingy() {}
  virtual int id() const = 0;
};

//template trick to force registration.
template < typename Derived >
struct registered_thingy : thingy
{
  registered_thingy() : my_id(my_static_id) {} 

  int id() const { return my_id; }
private:
  int my_id;
  static int my_static_id;
}
template < typename Derived >
int registered_thingy<Derived>::my_static_id = 
  container::instance().register_thingy(new Derived);

现在，在 concrete_thingy.cpp 文件中，我有:

struct my_concrete_thingy : registered_thingy<my_concrete_thingy>
{
  my_concrete_thingy() {} // registered_thingy's constructor not called otherwise
};

#pragma comment (linker, "/export:concrete_thingy")
#pragma comment (linker, "/export:concrete_thingy::my_static_id")
#pragma comment (linker, "/export:registered_thingy<concrete_thingy>::my_static_id")