使用 Thrust 生成均匀分布的随机数

Thrust has random generators you can use to produce sequences of random numbers. To use them with a device vector you will need to create a functor which returns a different element of the random generator sequence. The most straightforward way to do this is using a transformation of a counting iterator. A very simple complete example (in this case generating random single precision numbers between 1.0 and 2.0) could look like:

#include <thrust/random.h>
#include <thrust/device_vector.h>
#include <thrust/transform.h>
#include <thrust/iterator/counting_iterator.h>
#include <iostream>

struct prg
{
    float a, b;

    __host__ __device__
    prg(float _a=0.f, float _b=1.f) : a(_a), b(_b) {};

    __host__ __device__
        float operator()(const unsigned int n) const
        {
            thrust::default_random_engine rng;
            thrust::uniform_real_distribution<float> dist(a, b);
            rng.discard(n);

            return dist(rng);
        }
};


int main(void)
{
    const int N = 20;

    thrust::device_vector<float> numbers(N);
    thrust::counting_iterator<unsigned int> index_sequence_begin(0);

    thrust::transform(index_sequence_begin,
            index_sequence_begin + N,
            numbers.begin(),
            prg(1.f,2.f));

    for(int i = 0; i < N; i++)
    {
        std::cout << numbers[i] << std::endl;
    }

    return 0;
}

在本例中，仿函数 prg 将随机数的上下界作为参数，(0.f,1.f) 作为默认.请注意，为了每次调用变换操作时都有不同的向量，您应该使用初始化为不同起始值的计数迭代器.