有没有一种标准方法来比较 C++ 中的两个范围?
范围是指一对迭代器.在伪 C++ 中:
By range I mean a pair of iterators. In pseudo C++:
std::vector<int> v1 = { 1, 2, 3, 4, 5 };
std::vector<int> v2 = { 2, 3, 4 };
if( std::compare_range( v1.begin() + 1, v1.end() - 1, v2.begin(), v2.end() ) {
std::cout << "Alright
";
}
compare_range 当然是我正在寻找的功能.
compare_range being of course the function I'm looking for.
免责声明:我知道，这是一个非常简单的函数.但像所有程序员一样，我尽量偷懒;-)
Disclaimer: This is a pretty trivial function to write, I know. But like all programmers, I try to be lazy ;-)
推荐答案
std::equal就是你要找的函数模板.
std::equal is the function template you are looking for.
if (std::equal(v1.begin() + 1, v1.end() - 1, v2.begin())
{
std::cout << "Alright
";
}
注意 std::equal 只接受三个参数，而不是四个.
Note that std::equal only takes three arguments, not four.
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