我可以通过添加一个数字来增加一个迭代器吗?
我可以使用迭代器进行正常计算，即通过添加一个数字来增加它吗?
Can I do normal computations with iterators, i.e. just increment it by adding a number?
例如，如果我想删除元素 vec[3]，我可以这样做吗:
As an example, if I want to remove the element vec[3], can I just do this:
std::vector<int> vec;
for(int i = 0; i < 5; ++i){
vec.push_back(i);
}
vec.erase(vec.begin() + 3); // removes vec[3] element
它适用于我 (g++)，但我不确定它是否保证有效.
It works for me (g++), but I'm not sure if it is guaranteed to work.
推荐答案
如果迭代器是随机访问迭代器就可以工作，vector的迭代器是哪个(见参考).可以使用 STL 函数 std::advance推进通用迭代器，但由于它不返回迭代器，我倾向于使用 + 如果可用，因为它看起来更干净.
It works if the iterator is a random access iterator, which vector's iterators are (see reference). The STL function std::advance can be used to advance a generic iterator, but since it doesn't return the iterator, I tend use + if available because it looks cleaner.
C++11 笔记
现在有 std::next和 std::prev，做返回迭代器，所以如果你在模板领域工作，你可以使用它们来推进通用迭代器并且仍然有干净的代码.
Now there is std::next and std::prev, which do return the iterator, so if you are working in template land you can use them to advance a generic iterator and still have clean code.
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