移动向量是否会使迭代器无效?

If I have an iterator into vector a, then I move-construct or move-assign vector b from a, does that iterator still point to the same element (now in vector b)? Here's what I mean in code:

#include <vector>
#include <iostream>

int main(int argc, char *argv[])
{
    std::vector<int>::iterator a_iter;
    std::vector<int> b;
    {
        std::vector<int> a{1, 2, 3, 4, 5};
        a_iter = a.begin() + 2;
        b = std::move(a);
    }
    std::cout << *a_iter << std::endl; // Is a_iter valid here?
    return 0;
}

a_iter 是否仍然有效，因为 a 已被移动到 b 中，还是迭代器因移动而失效?作为参考，std::vector::swap 不会使迭代器失效.