OpenCV drawMatches――queryIdx 和 trainIdx
这是 OpenCV 的 drawMatches()
函数:p>
This is OpenCV's drawMatches()
function:
void drawMatches(Mat img1, vector<KeyPoint> keypoints1,
Mat img2, vector<KeyPoint> keypoints2,
vector<DMatch> matches,
Mat outImg) //want keypoints1[i] = keypoints2[matches[i]]
请注意,matches
属于 vector
类型.这是 DMatch
构造函数:
Notice that matches
is of type vector<DMatch>
. Here is the DMatch
constructor:
DMatch(int queryIdx, int trainIdx, float distance)
据推测,queryIdx
是一组关键点的索引,trainIdx
是另一组关键点的索引.
Presumably, queryIdx
is an index into one set of keypoints, and trainIdx
is an index into the other set of keypoints.
问题:queryIdx
索引到 keypoints1
是否真的,而 trainIdx
索引到 keypoints2
?或者,是否反过来?
The question: Is it true that queryIdx
indexes into keypoints1
, and trainIdx
indexes into keypoints2
? Or, is it the other way around?
推荐答案
这取决于你如何获得 matches
.
That depends on how you get matches
.
如果按顺序调用匹配函数:
If you call match function in the order:
match(descriptor_for_keypoints1, descriptor_for_keypoints2, matches)
那么queryIdx
指keypoints1
,trainIdx
指keypoints2
,反之亦然.
then queryIdx
refers to keypoints1
and trainIdx
refers to keypoints2
, or vice versa.
相关文章