你如何在 C++ 中模拟使用 RAII 的类

2022-01-08 00:00:00 mocking unit-testing c++

这是我的问题，我想模拟一个在初始化时创建线程并在销毁时关闭它的类.我的模拟类没有理由实际创建和关闭线程.但是，为了模拟一个类，我继承了它.当我创建模拟类的新实例时，会调用基类构造函数，从而创建线程.当我的模拟对象被销毁时，基类析构函数被调用，试图关闭线程.

Here's my issue, I'd like to mock a class that creates a thread at initialization and closes it at destruction. There's no reason for my mock class to actually create and close threads. But, to mock a class, I have inherit from it. When I create a new instance of my mock class, the base classes constructor is called, creating the thread. When my mock object is destroyed, the base classes destructor is called, attempting to close the thread.

如何在不处理实际资源的情况下模拟 RAII 类?

How does one mock an RAII class without having to deal with the actual resource?

推荐答案

改为创建一个描述类型的接口，并让真实类和模拟类都继承自该接口.所以如果你有:

You instead make an interface that describes the type, and have both the real class and the mock class inherit from that. So if you had:

class RAIIClass {
 public:
  RAIIClass(Foo* f);
  ~RAIIClass();
  bool DoOperation();

 private:
  ...
};

你会做一个这样的界面:

You would make an interface like:

class MockableInterface {
 public:
  MockableInterface(Foo* f);
  virtual ~MockableInterface();
  virtual bool DoOperation() = 0;
};

然后从那里出发.

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